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k^2-17k-84=0
a = 1; b = -17; c = -84;
Δ = b2-4ac
Δ = -172-4·1·(-84)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-25}{2*1}=\frac{-8}{2} =-4 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+25}{2*1}=\frac{42}{2} =21 $
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